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# Find normal depth in a 20.0-foot-wide concrete rectangular channel having a slop

Sep 1, 2021 | Uncategorized

Find normal depth in a 20.0-foot-wide concrete rectangular channel having a slope of 0.020 ft/ft and carrying a flow of 700 cfs. Use trial and Error method. n=0.014
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HW
2022;
Find normal depth in a 20.0-foot-wide concrete rectangular channel having a slope of
0.020 ft/ft and carrying a flow of 700 cfs. Use trial and Error method. n=0.014
F0A0;
Manning2019;s Equation
1.49 2 3 1 2
v=
R so
n
2013; English units
v = velocity
so = slope of channel
n = roughness factor
Manning2019;s Equation (cont2019;d.)
1 23 12
v = R so
n
2013; SI units
v = velocity
so= slope of channel
n = roughness factor
Manning2019;s Equation (cont2019;d.)
2022; Used to find velocity if normal depth is
known
2022; Q can also be determined
a = cross-sectional area
1.49 2 3 1 2
Q= a
R so
n
a 23 12
Q = R so
n
F0A0;
Manning2019;s Equation (cont2019;d.)
2022; Roughness factor
2013; Empirical number that describes channel
roughness
2013; Not the same as 2018;f2019; in Bernoulli2019;s equation
Channel Flow
2022; Typical engineering problems involving
uniform flow:
2013; Compute discharge when normal depth is
known
2013; Compute normal depth when discharge is
known
Example
2022; Find the quantity of flow Q in a concrete
rectangular channel having a width of 12.0
feet, a slope of 0.0200 ft/ft, and a normal
depth, Dn, of 1.58 feet. Let n = 0.013
Example
2022; Find normal depth in a 10.0-foot-wide
concrete rectangular channel having a
slope of 0.0150 ft/ft and carrying a flow of
400. cfs
2026;