Find normal depth in a 20.0-foot-wide concrete rectangular channel having a slope of 0.020 ft/ft and carrying a flow of 700 cfs. Use trial and Error method. n=0.014

hw.docx

channel_flowxxx.pptx

Unformatted Attachment Preview

HW

2022;

Find normal depth in a 20.0-foot-wide concrete rectangular channel having a slope of

0.020 ft/ft and carrying a flow of 700 cfs. Use trial and Error method. n=0.014

F0A0;

Manning2019;s Equation

1.49 2 3 1 2

v=

R so

n

2013; English units

v = velocity

R = hydraulic radius

so = slope of channel

n = roughness factor

Manning2019;s Equation (cont2019;d.)

1 23 12

v = R so

n

2013; SI units

v = velocity

R = hydraulic radius

so= slope of channel

n = roughness factor

Manning2019;s Equation (cont2019;d.)

2022; Used to find velocity if normal depth is

known

2022; Q can also be determined

a = cross-sectional area

1.49 2 3 1 2

Q= a

R so

n

a 23 12

Q = R so

n

F0A0;

Manning2019;s Equation (cont2019;d.)

2022; Roughness factor

2013; Empirical number that describes channel

roughness

2013; Not the same as 2018;f2019; in Bernoulli2019;s equation

Channel Flow

2022; Typical engineering problems involving

uniform flow:

2013; Compute discharge when normal depth is

known

2013; Compute normal depth when discharge is

known

Example

2022; Find the quantity of flow Q in a concrete

rectangular channel having a width of 12.0

feet, a slope of 0.0200 ft/ft, and a normal

depth, Dn, of 1.58 feet. Let n = 0.013

Example

2022; Find normal depth in a 10.0-foot-wide

concrete rectangular channel having a

slope of 0.0150 ft/ft and carrying a flow of

400. cfs

2026;

Purchase answer to see full

attachment